Generic MMPDS Mechanical Properties Table – Decipher the Terms

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In this post I will try to explain how to read and understand a generic MMPDS mechanical properties table. The material we will consider is Aluminum Alloy 2024-T351. It is one of the most commonly used materials in the aerospace industry. T351 here refers to the ‘Temper’ produced using heat treatment.

But first, let us look at the material grain directions L, LT and ST. In this case, we are looking at a rolled raw material plate of a big chunk of this metal alloy. Click the image below to learn more about the material and heat treat labels.

Rolled Palte Grain Directions:

We can see three different grain directions above:

  1. L Direction: This is the strongest ‘Long’ (L) direction along the dominant grain direction shown in blue in the figure above
  2. LT Direction: This is the orthogonal ‘Long Transverse’ (LT) grain direction in the plane of the plate, shown in red above
  3. ST Direction: Finally we have the ‘Short Transverse’ (ST) grain direction, the weakest grain direction shown in green above

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So why did we first discuss the grain directions? Because these directions have a significant impact on the mechanical properties. If a part is manufactured using this rolled plate, the properties depend on the grain direction that the critical part feature lies along. A common example would be lugs or fittings machined from this plate. Now let us dig into the properties table itself. Shown below is an extract from the MMPDS document.

Figure 2: Generic MMPDS Mechanical Properties Table, 2024 Plate

Al 2024-T351, Specification and Form:

We can see from the table above, the title at the top lists the name of the material and the raw material form (sheet and plate). Sheet forms are generally thinner, and plate forms are a bit thicker. Then come the material alloy procurement specifications (AMS specifications), raw material form (plate), the heat treat temper (T351), plate thickness (from 0.25″ thru 4.0″) and the statistical basis (A-Basis or B-Basis allowables).

A-Basis:

This value is the more stringent statistically reduced value from all the tested values. Without getting into too much detail, A-Basis is required when there is no redundant (or alternative) load path in case of a failure of a primary load path member, for example the lug of a fitting at the critical joint along the load path.

B-Basis:

This value is the less stringent statistically reduced value from all the tested values. Without getting into too much detail, B-Basis can be used with the approval of the authorities, when there is a redundant (or alternative) load path in case of a failure of a primary load path member, for example a panel pin in a composite sandwich panel joint made from many panel pins.

Al 2024-T351 Properties: Units in ksi (x10^3 psi)

Ftu: First mechanical property is Ftu, ultimate tensile strength. This is the value used in the most tensile section margin of safety calculations.

Fty: Then comes Fty, yield strength. This value must not be exceeded for limit loads (ultimate loads/1.5).

Fcy: Then comes Fcy, compressive yield strength. However the critical compressive stress is calculated using standard methods found in literature such as Bruhn and Niu.

Fsu: Then comes Fsu, ultimate shear strength. This value is used in shear margin of safety, or in interactive (tensile and shear interaction) margin of safety calculations.

Fbru and Fbry: Then we have Fbru and Fbry, ultimate and yield bearing strength values. These values are used in checking the material in bearing, such as a fastener bearing against the fastener hole. The selection of these values also depends on what is called e/D (edge distance ratio: hole center to edge distance ‘e’ over bolt hole diameter ‘D’).

e%: Then we have % elongation, this is the total strain percent at ultimate failure of the test coupon. Typically used to evaluate how much compliance the material has before failure.

 

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Elastic Constants: Finally we have the elastic constants, E, G and nu - Young's Modulus (x10^3 ksi) in this case is 10.7x10^6 psi, Shear Modulus (x10^3 ksi) in this case is 10.9x10^6 psi and Poisson's ratio of 0.33.

Weight Density: Finally at the bottom we see the material density (weight density not mass density), in this case it is 0.1 lbf/in^3. This value is critical when defining the material in the FEM Program for inertia loading and center of gravity, so make sure you get this right.

We generally do not worry about the thermal stuff.

ALRIGHT, I hope this gives you at least an idea of what the Generic MMPDS Mechanical Properties Table is all about, how to read and use it in real life.

 


Surya Batchu
Surya Batchu

Surya Batchu is the founder of Stress Ebook LLC. A senior stress engineer specializing in aerospace stress analysis and finite element analysis, Surya has close to a decade and a half of real world industry experience. He shares his expertise with you on this blog and the website via paid courses, so you can benefit from it and get ahead in your own career.

  • Steven Katzeff

    You state that elongation is “the total strain percent at ultimate failure of the test coupon”. Is this the plastic strain or elastic+plastic strain at failure?

    • stressebookllc

      Excellent question Steven. The definition is ‘Total gauge length at failure Lx minus Initial Length Lo divided by Initial Length Lo’ * 100. So if we take a round steel bar, this should include both the elastic and the plastic strains, at least that is my understanding. Sometimes the necking of the specimen under the grips may produce erroneous results, so air activated self adjusting grips with rubber padding help with accuracy. Here is a link that may help:
      http://www.engineersedge.com/material_science/ductility.htm

  • Steven Katzeff

    I would say on the contrary-since the gauge length at failure has already realised its elastic strain after failure, i.e. it has sprung back a little, then the elongation should be the plastic strain only.

    • stressebookllc

      The total length at failure is between the grips. The specimen after failure may spring back. But if the grips spring back (which I am not sure they do, they must remain at the final failure position) then I’d think you have a point. But I have been wrong before and I would love to be corrected so I can learn too..

      • Phill Le M

        It is probably a value inbetween as the necking will strain harden the material and the elasticity that was there originally will not give a proportionately identical “elastic recovery” in the direction of load application post plastic distortion and failure, being mindful that the cross sectional area at the necked region has reduced due to overall volumetric strain involved in the “necking” process so I doubt a 100% accurate / satisfactory answer will be possible as this is likely to vary from material to material.

        • stressebookllc

          Correct, if the reduced necking area is used, the stress strain curve slope would never come back down.